What is the range of (9-3x)/(x-4) ?

The range of (9-3x)/(x-4) is f(x) -3

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range of (9-3x)/(x-4)

range

\frac{9 - 3 x}{x - 4}

f (x) < - 3 or f (x) > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{9 - 3 x}{x - 4}

Inverse of

\frac{9 - 3 x}{x - 4} : \frac{9 + 4 x}{x + 3}

\frac{9 + 4 x}{x + 3}

Find the domain of each inverse function

Domain of

\frac{9 + 4 x}{x + 3} : x < - 3 or x > - 3

Combine the intervals

f (x) < - 3 or f (x) > - 3

f (x) = - 3 tan (\frac{1}{2} x)

(- 2, - 2), (1, - 2)

h (x) = \frac{6}{( x + 5 ) ( x - 3 )}

\frac{y - 10}{y ^{2} + 3}

2 x - 44

What is the range of (9-3x)/(x-4) ?
The range of (9-3x)/(x-4) is f(x)<-3\lor f(x)>-3