What is the perpendicular y=3x-1,(-1,-1) ?

The perpendicular y=3x-1,(-1,-1) is y=-1/3 x-4/3

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perpendicular y=3x-1,(-1,-1)

perpendicular

y = 3 x - 1, (- 1, - 1)

y = - \frac{1}{3} x - \frac{4}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 1

that passes through

(- 1, - 1)

Find the slope of

y = 3 x - 1 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 1, - 1) : y = - \frac{1}{3} x - \frac{4}{3}

y = - \frac{1}{3} x - \frac{4}{3}

f (x) = \frac{x ^{3}}{2 - x}

f (x) = 8 x^{3} + x^{2} + 8 x

f (x) = \frac{5}{( x - 3 ) ^{2}}

f (x) = \frac{1}{2} x + 1

\frac{( x ^{2} - 4 )}{x ^{3} + x ^{2} - 4 x - 4}

What is the perpendicular y=3x-1,(-1,-1) ?
The perpendicular y=3x-1,(-1,-1) is y=-1/3 x-4/3