What is the domain of f(x)=sqrt(x)+4 ?

The domain of f(x)=sqrt(x)+4 is x>= 0

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domain of f(x)=sqrt(x)+4

domain

f (x) = x + 4

x \geq 0

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = 5 sec (x) - 4 x

f (x) = - x^{3} - 6 x^{2} + 3

f (x) = \frac{5 x ^{2} - 3}{x + 2}

x + 15

f (x) = \frac{1}{x + 2}