What is the domain of f(x)=sqrt(\sqrt{x^2-1)-1} ?

The domain of f(x)=sqrt(\sqrt{x^2-1)-1} is x = sqrt(2)

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domain of f(x)=sqrt(\sqrt{x^2-1)-1}

domain

f (x) = x^{2} - 1 - 1

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = \frac{2 x ^{2}}{x ^{2} + 1}

f (x) = \frac{x ^{2} - 4}{8 x ^{2}}

f (x) = - 4 x^{3}

f (x) = 5 - 7 x

5 x + 3 y = 15

What is the domain of f(x)=sqrt(\sqrt{x^2-1)-1} ?
The domain of f(x)=sqrt(\sqrt{x^2-1)-1} is x<=-sqrt(2)\lor x>= sqrt(2)