What is the shift 1/2 cos(3x+pi/2) ?

The shift 1/2 cos(3x+pi/2) is Phase:-pi/6 , Vertical:0

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shift 1/2 cos(3x+pi/2)

shift

\frac{1}{2} cos (3 x + \frac{π}{2})

Phase : - \frac{π}{6}, Vertical : 0

Solution steps

f (x) = \frac{1}{2} cos (3 x + \frac{π}{2})

g (B x - C) = cos (3 x + \frac{π}{2}), B = 3, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{3}

- \frac{π}{6}

The vertical shift

D

0

0

(- 2.4) (7)

\frac{3}{4} \cdot (x^{2} - 1)^{\frac{2}{3}}

- 2 sin (\frac{x}{4}) + 3

\frac{1}{2} \cdot 4^{x}

f (x) = x^{2} + x + 2

What is the shift 1/2 cos(3x+pi/2) ?
The shift 1/2 cos(3x+pi/2) is Phase:-pi/6 , Vertical:0