What is the inverse of f(x)=x^2+3x-1 ?

The inverse of f(x)=x^2+3x-1 is (-3+sqrt(4x+13))/2 ,(-3-sqrt(4x+13))/2

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inverse of f(x)=x^2+3x-1

inverse

f (x) = x^{2} + 3 x - 1

\frac{- 3 + 4 x + 13}{2}, \frac{- 3 - 4 x + 13}{2}

Solution steps

y = x^{2} + 3 x - 1

Replace

x

with

y

x = y^{2} + 3 y - 1

Solve for

y, x = y^{2} + 3 y - 1

\frac{- 3 + 4 x + 13}{2}, \frac{- 3 - 4 x + 13}{2}

- x - 5

f (x) = \frac{x + 32}{x - 6}

f (x) = \frac{3 x}{x - 2}

(0, - 3), (- 1, 15)

f (x) = \frac{( - 9 - 8 x )}{x - 1}

What is the inverse of f(x)=x^2+3x-1 ?
The inverse of f(x)=x^2+3x-1 is (-3+sqrt(4x+13))/2 ,(-3-sqrt(4x+13))/2