What is the extreme f(x)=x^3-x^2-8x ?

The extreme f(x)=x^3-x^2-8x is Maximum(-4/3 , 176/27),Minimum(2,-12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-x^2-8x

extreme points

f (x) = x^{3} - x^{2} - 8 x

Maximum (- \frac{4}{3}, \frac{176}{27}), Minimum (2, - 12)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{4}{3},

Decreasing

: - \frac{4}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{4}{3}

into

x^{3} - x^{2} - 8 x : \frac{176}{27}

Maximum (- \frac{4}{3}, \frac{176}{27})

Plug

x = 2

into

x^{3} - x^{2} - 8 x : - 12

Minimum (2, - 12)

Maximum (- \frac{4}{3}, \frac{176}{27}), Minimum (2, - 12)

f (x) = 7^{x - 2}

\frac{x}{5} + \frac{y}{2} = 1

f (x) = x^{2} + 2 x + 25

y = x^{2} - 9

f (x) = \frac{x ^{2} - 3}{2}

What is the extreme f(x)=x^3-x^2-8x ?
The extreme f(x)=x^3-x^2-8x is Maximum(-4/3 , 176/27),Minimum(2,-12)