What is the critical f(x)= 1/3 x^3-x^2-8x ?

The critical f(x)= 1/3 x^3-x^2-8x is x=-2,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)= 1/3 x^3-x^2-8x

critical points

f (x) = \frac{1}{3} x^{3} - x^{2} - 8 x

x = - 2, x = 4

Solution steps

\frac{1}{3} x^{3} - x^{2} - 8 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{3} x^{3} - x^{2} - 8 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 4

f (x) = \frac{9}{5} + 32

f (x) = \frac{1}{x ^{2} + 6 x - 7}

f (x) = x^{4} - 4 x^{3} + 3 x + 5

f (x) = \frac{8 x - 3}{x}

y - 6 = (x + 2)^{2}

What is the critical f(x)= 1/3 x^3-x^2-8x ?
The critical f(x)= 1/3 x^3-x^2-8x is x=-2,x=4