What is the inverse of f(x)=(x+1)^2+3 ?

The inverse of f(x)=(x+1)^2+3 is sqrt(x-3)-1,-sqrt(x-3)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x+1)^2+3

inverse

f (x) = (x + 1)^{2} + 3

x - 3 - 1, - x - 3 - 1

Solution steps

y = (x + 1)^{2} + 3

Replace

x

with

y

x = (y + 1)^{2} + 3

Solve for

y, x = (y + 1)^{2} + 3

x - 3 - 1, - x - 3 - 1

f (x) = \frac{4 x ^{2} - 81}{2 x - 20}

e^{\frac{1}{x}}

f (x) = t^{2} + 4

y = 2 x^{3} - 3 x^{2} - 9

- (x - 4)^{2} + 1

What is the inverse of f(x)=(x+1)^2+3 ?
The inverse of f(x)=(x+1)^2+3 is sqrt(x-3)-1,-sqrt(x-3)-1