What is the inverse of 2ln(x^2+1) ?

The inverse of 2ln(x^2+1) is sqrt(e^{x/2)-1},-sqrt(e^{x/2)-1}

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inverse of 2ln(x^2+1)

inverse

2 ln (x^{2} + 1)

e^{\frac{x}{2}} - 1, - e^{\frac{x}{2}} - 1

Solution steps

y = 2 ln (x^{2} + 1)

Replace

x

with

y

x = 2 ln (y^{2} + 1)

Solve for

y, x = 2 ln (y^{2} + 1)

e^{\frac{x}{2}} - 1, - e^{\frac{x}{2}} - 1

f (x) = \frac{2 x - 4}{x ^{2} - 9}

f (x) = csc (x)

f (x) = 3 x^{5} - 30 x^{4}

f (x) = 6 x - 3

(8, 20), (2, 2)

What is the inverse of 2ln(x^2+1) ?
The inverse of 2ln(x^2+1) is sqrt(e^{x/2)-1},-sqrt(e^{x/2)-1}