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Popular >

midpoint (10,-3),(2,-4)

Solution

midpoint

(10, - 3), (2, - 4)

Solution

(6, - \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (10, - 3), (x_{2}, y_{2}) = (2, - 4)

= (\frac{2 + 10}{2}, \frac{- 4 - 3}{2})

Refine

= (6, - \frac{7}{2})

Popular Examples

inverse of 4+2*e^{-x}inverse

4 + 2 \cdot e^{- x}

distance (1/3 ,-5/4),(3/4 ,-4)distance

(\frac{1}{3}, - \frac{5}{4}), (\frac{3}{4}, - 4)

domain of f(x)=x^3-2 domain

f (x) = x^{3} - 2

asymptotes of f(x)=(3x-1)/(2x+5)asymptotes

f (x) = \frac{3 x - 1}{2 x + 5}

midpoint (-11,4),(-2,-5)midpoint

(- 11, 4), (- 2, - 5)

Frequently Asked Questions (FAQ)

What is the midpoint (10,-3),(2,-4) ?
The midpoint (10,-3),(2,-4) is (6,-7/2)