What is the distance (1/3 ,-5/4),(3/4 ,-4) ?

The distance (1/3 ,-5/4),(3/4 ,-4) is (sqrt(557))/(6sqrt(2))

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distance (1/3 ,-5/4),(3/4 ,-4)

distance

(\frac{1}{3}, - \frac{5}{4}), (\frac{3}{4}, - 4)

\frac{557}{6 2}

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(\frac{1}{3}, - \frac{5}{4})

and

(\frac{3}{4}, - 4)

= (\frac{3}{4} - \frac{1}{3})^{2} + (- 4 - (- \frac{5}{4}))^{2}

Simplify

= \frac{557}{6 2}

f (x) = x^{3} - 2

f (x) = \frac{3 x - 1}{2 x + 5}

(- 11, 4), (- 2, - 5)

f (x) = (\frac{x}{4}) + \frac{1}{2}

g (x) = - x^{2} + 4

What is the distance (1/3 ,-5/4),(3/4 ,-4) ?
The distance (1/3 ,-5/4),(3/4 ,-4) is (sqrt(557))/(6sqrt(2))