en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of g(x)=-x^2+4

Solution

range

g (x) = - x^{2} + 4

Solution

f (x) \leq 4

+1

Interval Notation

(- \infty, 4]

Solution steps

Vertex of

- x^{2} + 4 :

Maximum

(0, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 4)

f (x) \leq 4

Popular Examples

inverse of (-x+7)/(5+2x)inverse

\frac{- x + 7}{5 + 2 x}

critical x^{2/3}(x-5)critical points

x^{\frac{2}{3}} (x - 5)

simplify (4.6)(-3.3)simplify

(4.6) (- 3.3)

intercepts of x^2+8x+14 intercepts

x^{2} + 8 x + 14

extreme 1/(X^2)extreme points

\frac{1}{X ^{2}}

Frequently Asked Questions (FAQ)

What is the range of g(x)=-x^2+4 ?
The range of g(x)=-x^2+4 is f(x)<= 4