What is the domain of f(x)= 1/(sqrt(x)-5) ?

The domain of f(x)= 1/(sqrt(x)-5) is 0 25

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domain of f(x)= 1/(sqrt(x)-5)

domain

f (x) = \frac{1}{x - 5}

0 \leq x < 25 or x > 25

Interval Notation

[0, 25) \cup (25, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 25

Combine real regions and undefined points for final function domain

0 \leq x < 25 or x > 25

f (x) = 5 sin (x) + 5 cos (x)

x - 7

ln (7)

D (r) = \frac{23}{20} r + \frac{4}{3}

f (x) = x^{4} - x^{2} + 2

What is the domain of f(x)= 1/(sqrt(x)-5) ?
The domain of f(x)= 1/(sqrt(x)-5) is 0<= x<25\lor x>25