What is the domain of f(x)=sqrt(x+15) ?

The domain of f(x)=sqrt(x+15) is x>=-15

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domain of f(x)=sqrt(x+15)

domain

f (x) = x + 15

x \geq - 15

Interval Notation

[- 15, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 15

The function domain

x \geq - 15

(- 3, 2), (1, - 1)

a csc (3^{x^{2}} + ln (x))

f (x) = \frac{1}{( x + 4 ) ^{2}} - 5

f (x) = - x^{2} - 2 x - 1

\frac{4 x + 3}{x ^{2} + 3 x}