What is the domain of (x-5)/(x^2-1) ?

The domain of (x-5)/(x^2-1) is x 1

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domain of (x-5)/(x^2-1)

domain

\frac{x - 5}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 14 x^{3} - 10

2 - 3^{5 - x}

(2 x - 1)^{7} (x + 5)^{6}

\frac{2 x + 1}{3 x ^{2}}

f (x) = \frac{( x + 1 ) ^{2}}{2 x - 1}

What is the domain of (x-5)/(x^2-1) ?
The domain of (x-5)/(x^2-1) is x<-1\lor-1<x<1\lor x>1