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Popular >

midpoint (5,-14),(12,-9)

Solution

midpoint

(5, - 14), (12, - 9)

Solution

(\frac{17}{2}, - \frac{23}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (5, - 14), (x_{2}, y_{2}) = (12, - 9)

= (\frac{12 + 5}{2}, \frac{- 9 - 14}{2})

Refine

= (\frac{17}{2}, - \frac{23}{2})

Popular Examples

asymptotes of y=x^4-16x^2 asymptotes

y = x^{4} - 16 x^{2}

domain of f(x)= 1/(sqrt(z-1))domain

f (x) = \frac{1}{z - 1}

range of f(x)=x^2+5 range

f (x) = x^{2} + 5

domain of (sqrt(x-3))/(x-10)domain

\frac{x - 3}{x - 10}

inflection 3x^4-20x^3+24x^2 inflection points

3 x^{4} - 20 x^{3} + 24 x^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (5,-14),(12,-9) ?
The midpoint (5,-14),(12,-9) is (17/2 ,-23/2)