What is the extreme f(x)=2.2+2.2x-0.6x^2 ?

The extreme f(x)=2.2+2.2x-0.6x^2 is Maximum(11/6 ,4.21666…)

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extreme f(x)=2.2+2.2x-0.6x^2

extreme points

f (x) = 2.2 + 2.2 x - 0.6 x^{2}

Maximum (\frac{11}{6}, 4.21666 \dots)

Solution steps

f^{'} (x) = - 1.2 x + 2.2

Find intervals:

Increasing

: - \infty < x < \frac{11}{6},

Decreasing

: \frac{11}{6} < x < \infty

Plug

x = \frac{11}{6}

into

2.2 + 2.2 x - 0.6 x^{2} : 4.21666 \dots

Maximum (\frac{11}{6}, 4.21666 \dots)

x^{3} - 9 x^{2} + 15 x - 8

f (x) = 3 x - 12

f (x) = e^{x}

f (x) = 4 + 6 x

2 x^{2} - 5 x + 3

What is the extreme f(x)=2.2+2.2x-0.6x^2 ?
The extreme f(x)=2.2+2.2x-0.6x^2 is Maximum(11/6 ,4.21666…)