What is the perpendicular y=8x-7,(-2,5) ?

The perpendicular y=8x-7,(-2,5) is y=-1/8 x+19/4

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perpendicular y=8x-7,(-2,5)

perpendicular

y = 8 x - 7, (- 2, 5)

y = - \frac{1}{8} x + \frac{19}{4}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 8 x - 7

that passes through

(- 2, 5)

Find the slope of

y = 8 x - 7 : m = 8

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(- 2, 5) : y = - \frac{1}{8} x + \frac{19}{4}

y = - \frac{1}{8} x + \frac{19}{4}

y = - 4 x^{2}

f (x) = \frac{x + 1}{x - 4}

\frac{x ^{2} - 9}{x - 3}

f (x) = \frac{x ^{2} + x - 2}{x + 1}

f (x) = x + \frac{81}{x}

What is the perpendicular y=8x-7,(-2,5) ?
The perpendicular y=8x-7,(-2,5) is y=-1/8 x+19/4