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Popular >

midpoint (-2,-8),(2,-3)

Solution

midpoint

(- 2, - 8), (2, - 3)

Solution

(0, - \frac{11}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, - 8), (x_{2}, y_{2}) = (2, - 3)

= (\frac{2 - 2}{2}, \frac{- 3 - 8}{2})

Refine

= (0, - \frac{11}{2})

Popular Examples

domain of f(x)=(x+2)/(x^2-2x+1)domain

f (x) = \frac{x + 2}{x ^{2} - 2 x + 1}

symmetry (y-3)^2=8(x-5)symmetry

(y - 3)^{2} = 8 (x - 5)

asymptotes of f(x)=(x^2+6x+9)/(x^3+7x^2)asymptotes

f (x) = \frac{x ^{2} + 6 x + 9}{x ^{3} + 7 x ^{2}}

domain of f(x)=sqrt(x^3+6x^2+8x)domain

f (x) = x^{3} + 6 x^{2} + 8 x

symmetry y^2-x-25=0 symmetry

y^{2} - x - 25 = 0

Frequently Asked Questions (FAQ)

What is the midpoint (-2,-8),(2,-3) ?
The midpoint (-2,-8),(2,-3) is (0,-11/2)