What is the perpendicular 9x+y=3,(3,6) ?

The perpendicular 9x+y=3,(3,6) is y= 1/9 x+17/3

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perpendicular 9x+y=3,(3,6)

perpendicular

9 x + y = 3, (3, 6)

y = \frac{1}{9} x + \frac{17}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

9 x + y = 3

that passes through

(3, 6)

Find the slope of

9 x + y = 3 : m = - 9

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{9}

Find the line with slope m=

\frac{1}{9}

and passing through

(3, 6) : y = \frac{1}{9} x + \frac{17}{3}

y = \frac{1}{9} x + \frac{17}{3}

f (x) = \frac{3}{2} x

\frac{5 x ^{2} + 6 x - 4}{x ^{2} + 1}

f (x) = (9 - x^{2}) + 2

f (x) = 1 + 7 + x

- 2 sin (6 x)

What is the perpendicular 9x+y=3,(3,6) ?
The perpendicular 9x+y=3,(3,6) is y= 1/9 x+17/3