What is the domain of f(t)=sqrt(t+7) ?

The domain of f(t)=sqrt(t+7) is t>=-7

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domain of f(t)=sqrt(t+7)

domain

f (t) = t + 7

t \geq - 7

Interval Notation

[- 7, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 7

The function domain

t \geq - 7

\frac{1}{x ^{2} - 4}

(x^{3} - x - 18)^{4}

y = - 4 x^{2} + 8 x

f (x) = \frac{( x + 1 )}{( x - 1 )}

f (x) = 3 x^{2} - x^{3}