What is the perpendicular 3/2 x+2y= 15/2 ,(-4,4) ?

The perpendicular 3/2 x+2y= 15/2 ,(-4,4) is y= 4/3 x+28/3

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perpendicular 3/2 x+2y= 15/2 ,(-4,4)

perpendicular

\frac{3}{2} x + 2 y = \frac{15}{2}, (- 4, 4)

y = \frac{4}{3} x + \frac{28}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

\frac{3}{2} x + 2 y = \frac{15}{2}

that passes through

(- 4, 4)

Find the slope of

\frac{3}{2} x + 2 y = \frac{15}{2} : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(- 4, 4) : y = \frac{4}{3} x + \frac{28}{3}

y = \frac{4}{3} x + \frac{28}{3}

7 x + 5 y = - 40

(11.2, - 2.2), (5.2, - 10.2)

f (x) = (7 x^{3} + 2)^{\frac{1}{5}}

7 sin (4 (t + 7)) - 8

f (x) = (x + 2)^{\frac{1}{5}}

What is the perpendicular 3/2 x+2y= 15/2 ,(-4,4) ?
The perpendicular 3/2 x+2y= 15/2 ,(-4,4) is y= 4/3 x+28/3