What is the extreme f(x)=(18-2x)^2x ?

The extreme f(x)=(18-2x)^2x is Maximum(3,432),Minimum(9,0)

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extreme f(x)=(18-2x)^2x

extreme points

f (x) = (18 - 2 x)^{2} x

Maximum (3, 432), Minimum (9, 0)

Solution steps

f^{'} (x) = 12 (x - 9) (x - 3)

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = 3

into

(18 - 2 x)^{2} x : 432

Maximum (3, 432)

Plug

x = 9

into

(18 - 2 x)^{2} x : 0

Minimum (9, 0)

Maximum (3, 432), Minimum (9, 0)

y = 34 x - 5

f (x) = \frac{\frac{x}{x + 3}}{\frac{x}{x + 3} + 3}

\frac{6}{x} + 3

\frac{3 x + 3}{x + 2}

f (x) = - 2^{x}

What is the extreme f(x)=(18-2x)^2x ?
The extreme f(x)=(18-2x)^2x is Maximum(3,432),Minimum(9,0)