What is the domain of f(x)=sqrt(t-16) ?

The domain of f(x)=sqrt(t-16) is t>= 16

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domain of f(x)=sqrt(t-16)

domain

f (x) = t - 16

t \geq 16

Interval Notation

[16, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 16

The function domain

t \geq 16

5 x^{2} - 4 y^{2} = 2

(- 3, - 4), (- 5, - 3)

f (x) = - x^{2} + 4 x - 4

f (x) = - x^{4} + 8 x^{2} + 6

f (x) = \frac{1}{2 - 3 x}