What is the critical f(x)=-x^2+4x-4 ?

The critical f(x)=-x^2+4x-4 is x=2

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critical f(x)=-x^2+4x-4

critical points

f (x) = - x^{2} + 4 x - 4

x = 2

Solution steps

- x^{2} + 4 x - 4

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

- x^{2} + 4 x - 4 : - \infty < x < \infty

All critical points are in domain

x = 2

f (x) = - x^{4} + 8 x^{2} + 6

f (x) = \frac{1}{2 - 3 x}

f (x) = \frac{2 x - 1}{4 x + 6}

f (x) = 36 - t^{2}

y = x, (- 1, 3)