What is the domain of f(x)=(x^2+2)/(x-1) ?

The domain of f(x)=(x^2+2)/(x-1) is x 1

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domain of f(x)=(x^2+2)/(x-1)

domain

f (x) = \frac{x ^{2} + 2}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = - 2 (x - 1)^{2} + 27 = 9 + y

f (x) = - 2^{x + 1}

\frac{cos ( 8 θ ) - cos ( 4 θ )}{2}

2 - 3 cos (2 x)

lo g_{5} (x)

What is the domain of f(x)=(x^2+2)/(x-1) ?
The domain of f(x)=(x^2+2)/(x-1) is x<1\lor x>1