What is the domain of f(x)=-sqrt(2z+3) ?

The domain of f(x)=-sqrt(2z+3) is z>=-3/2

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domain of f(x)=-sqrt(2z+3)

domain

f (x) = - 2 z + 3

z \geq - \frac{3}{2}

Interval Notation

[- \frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

z \geq - \frac{3}{2}

The function domain

z \geq - \frac{3}{2}

f (x) = \frac{x ^{2} + 4 x - 3}{x ^{4} - 5 x ^{2} + 4}

f (x) = \frac{9 x}{x ^{2} - 1}

(13 - x)^{\frac{1}{6}}

(1, 4), (3, 6)

f (x) = x - 4

What is the domain of f(x)=-sqrt(2z+3) ?
The domain of f(x)=-sqrt(2z+3) is z>=-3/2