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Popular >

midpoint (8,13),(6,-1)

Solution

midpoint

(8, 13), (6, - 1)

Solution

(7, 6)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, 13), (x_{2}, y_{2}) = (6, - 1)

= (\frac{6 + 8}{2}, \frac{- 1 + 13}{2})

Refine

= (7, 6)

Popular Examples

domain of h(x)=sqrt(x-9)domain

h (x) = x - 9

critical f(x)=5x^4-10x^2+8 critical points

f (x) = 5 x^{4} - 10 x^{2} + 8

domain of f(x)=x^2-7x-30 domain

f (x) = x^{2} - 7 x - 30

parity f(x)=tan(e^t)+e^{tan(t)}parity

f (x) = tan (e^{t}) + e^{t a n (t)}

parallel 7x-12y=-32 parallel

7 x - 12 y = - 32

Frequently Asked Questions (FAQ)

What is the midpoint (8,13),(6,-1) ?
The midpoint (8,13),(6,-1) is (7,6)