What is the asymptotes of f(x)=((-2x^2))/(x^2+4x-5) ?

The asymptotes of f(x)=((-2x^2))/(x^2+4x-5) is Vertical: x=-5,x=1,Horizontal: y=-2

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asymptotes of f(x)=((-2x^2))/(x^2+4x-5)

asymptotes

f (x) = \frac{( - 2 x ^{2} )}{x ^{2} + 4 x - 5}

Vertical : x = - 5, x = 1, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2}}{x ^{2} + 4 x - 5} : x = - 5, x = 1

Horizontal Asymptotes of

\frac{- 2 x ^{2}}{x ^{2} + 4 x - 5} : y = - 2

Slant Asymptotes of

\frac{- 2 x ^{2}}{x ^{2} + 4 x - 5} :

None

Vertical : x = - 5, x = 1, Horizontal : y = - 2

f (x) = \frac{7}{8} - x

f (x) = - x^{3} + 27 x - 52

f (x) = \frac{4 x + 10}{2 x - 14}

f (t) = (\frac{1}{t - 2})

\frac{5}{1 - x}

What is the asymptotes of f(x)=((-2x^2))/(x^2+4x-5) ?
The asymptotes of f(x)=((-2x^2))/(x^2+4x-5) is Vertical: x=-5,x=1,Horizontal: y=-2