What is the domain of f(x)= 5/(x^2+24x+135) ?

The domain of f(x)= 5/(x^2+24x+135) is x -9

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domain of f(x)= 5/(x^2+24x+135)

domain

f (x) = \frac{5}{x ^{2} + 24 x + 135}

x < - 15 or - 15 < x < - 9 or x > - 9

Interval Notation

(- \infty, - 15) \cup (- 15, - 9) \cup (- 9, \infty)

Solution steps

Find undefined (singularity) points:

x = - 9, x = - 15

The function domain

x < - 15 or - 15 < x < - 9 or x > - 9

f (x) = (x - 4)^{2} - 9

\frac{3 x - 8}{2 x + 1}

y = \frac{5}{2} x - 8

f (x) = \frac{x ^{2} - 5 x + 3}{x - 3}

f (x) = \frac{2 x}{x ^{2} - 16}

What is the domain of f(x)= 5/(x^2+24x+135) ?
The domain of f(x)= 5/(x^2+24x+135) is x<-15\lor-15<x<-9\lor x>-9