What is the asymptotes of f(x)=(sqrt(1-x^2))/(2x+1) ?

The asymptotes of f(x)=(sqrt(1-x^2))/(2x+1) is Vertical: x=-1/2

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asymptotes of f(x)=(sqrt(1-x^2))/(2x+1)

asymptotes

f (x) = \frac{1 - x ^{2}}{2 x + 1}

Vertical : x = - \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{1 - x ^{2}}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{1 - x ^{2}}{2 x + 1} :

None

Slant Asymptotes of

\frac{1 - x ^{2}}{2 x + 1} :

None

Vertical : x = - \frac{1}{2}

f (x) = \frac{x + 4}{x - 3}

1 x + 1 y = 2

f (x) = x^{2} - 3 x - 2

f (x) = \frac{5}{x - 8}

f (x) = \frac{2 x + 3}{x + 4}

What is the asymptotes of f(x)=(sqrt(1-x^2))/(2x+1) ?
The asymptotes of f(x)=(sqrt(1-x^2))/(2x+1) is Vertical: x=-1/2