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Popular >

midpoint (7,-2),(-5,-2)

Solution

midpoint

(7, - 2), (- 5, - 2)

Solution

(1, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (7, - 2), (x_{2}, y_{2}) = (- 5, - 2)

= (\frac{- 5 + 7}{2}, \frac{- 2 - 2}{2})

Refine

= (1, - 2)

Popular Examples

inverse of f(x)=x^3-5 inverse

f (x) = x^{3} - 5

domain of f(x)=((2x^3-5))/(x^2+x-6)domain

f (x) = \frac{( 2 x ^{3} - 5 )}{x ^{2} + x - 6}

extreme f(x)= x/(x^2+1)extreme points

f (x) = \frac{x}{x ^{2} + 1}

inverse of y=f(x)=(2-5x)/(6-6x)inverse

y = f (x) = \frac{2 - 5 x}{6 - 6 x}

range of f(x)=6x range

f (x) = 6 x

Frequently Asked Questions (FAQ)

What is the midpoint (7,-2),(-5,-2) ?
The midpoint (7,-2),(-5,-2) is (1,-2)