What is the inverse of f(x)=x^2+4x-3 ?

The inverse of f(x)=x^2+4x-3 is -2+sqrt(x+7),-sqrt(x+7)-2

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inverse of f(x)=x^2+4x-3

inverse

f (x) = x^{2} + 4 x - 3

- 2 + x + 7, - x + 7 - 2

Solution steps

y = x^{2} + 4 x - 3

Replace

x

with

y

x = y^{2} + 4 y - 3

Solve for

y, x = y^{2} + 4 y - 3

- 2 + x + 7, - x + 7 - 2

3 x - 15

x^{2} + 81

\frac{3 x + 3}{2 x + 4}

f (x) = \frac{1}{2} x^{3} - 6

\frac{7 + \frac{1}{x}}{\frac{1}{x}}

What is the inverse of f(x)=x^2+4x-3 ?
The inverse of f(x)=x^2+4x-3 is -2+sqrt(x+7),-sqrt(x+7)-2