What is the extreme f(x)=x^3-3x+27 ?

The extreme f(x)=x^3-3x+27 is Maximum(-1,29),Minimum(1,25)

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extreme f(x)=x^3-3x+27

extreme points

f (x) = x^{3} - 3 x + 27

Maximum (- 1, 29), Minimum (1, 25)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 27 : 29

Maximum (- 1, 29)

Plug

x = 1

into

x^{3} - 3 x + 27 : 25

Minimum (1, 25)

Maximum (- 1, 29), Minimum (1, 25)

3 sin (x)

f (x) = 1 - x

f (x) = \frac{x + 1}{x ^{2} - 3 x - 4}

y = 6 x - 3

f (x) = 6 x^{2} + 1 - x

What is the extreme f(x)=x^3-3x+27 ?
The extreme f(x)=x^3-3x+27 is Maximum(-1,29),Minimum(1,25)