What is the range of f(x)=19-t^2 ?

The range of f(x)=19-t^2 is f(x)<= 19

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range of f(x)=19-t^2

range

f (x) = 19 - t^{2}

f (x) \leq 19

Interval Notation

(- \infty, 19]

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

19 - t^{2}

Inverse of

19 - t^{2} : - t + 19, - - t + 19

- t + 19, - - t + 19

Find the domain of each inverse function

Domain of

- t + 19 : t \leq 19

Domain of

- - t + 19 : t \leq 19

Combine the intervals

f (x) \leq 19

f (x) = 9 x^{2} + 8 x + 6

(4 - 9) - 5

f (x) = 1 + 4 + 5 x

f (x) = \frac{x ^{3}}{x ^{2} - 1}

y + 4 = 1 (x + 3)