What is the critical f(x)=(x^2)/(x+1) ?

The critical f(x)=(x^2)/(x+1) is x=-2,x=0

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critical f(x)=(x^2)/(x+1)

critical points

f (x) = \frac{x ^{2}}{x + 1}

x = - 2, x = 0

Solution steps

\frac{x ^{2}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x + 1} : x < - 1 or x > - 1

\frac{x ^{2}}{x + 1}

is not defined at

x = - 1

, therefore:

x = - 2, x = 0

f (x) = \frac{5}{( x - 3 ) ^{3}}

f (x) = \frac{2 x - 1}{x - 7}

f (x) = \frac{2 x ^{2}}{x ^{2} - 9}

f (x) = \frac{x ^{2} - 1}{x + 1}

f (x) = x^{3} + 3 x^{2}

What is the critical f(x)=(x^2)/(x+1) ?
The critical f(x)=(x^2)/(x+1) is x=-2,x=0