What is the domain of f(x)= 1/(x^2-8x-9) ?

The domain of f(x)= 1/(x^2-8x-9) is x 9

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domain of f(x)= 1/(x^2-8x-9)

domain

f (x) = \frac{1}{x ^{2} - 8 x - 9}

x < - 1 or - 1 < x < 9 or x > 9

Interval Notation

(- \infty, - 1) \cup (- 1, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = - 1

The function domain

x < - 1 or - 1 < x < 9 or x > 9

f (x) = 5 x - 12

f (x) = 3 x^{4} - 28 x^{3} + 60 x^{2}

(2, 7), (8, 9)

(6, - 5), (- 1, - 4)

f (x) = (x + 1)^{2} + 4

What is the domain of f(x)= 1/(x^2-8x-9) ?
The domain of f(x)= 1/(x^2-8x-9) is x<-1\lor-1<x<9\lor x>9