What is the inverse of f(x)=(x+1)^2+4 ?

The inverse of f(x)=(x+1)^2+4 is sqrt(x-4)-1,-sqrt(x-4)-1

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inverse of f(x)=(x+1)^2+4

inverse

f (x) = (x + 1)^{2} + 4

x - 4 - 1, - x - 4 - 1

Solution steps

y = (x + 1)^{2} + 4

Replace

x

with

y

x = (y + 1)^{2} + 4

Solve for

y, x = (y + 1)^{2} + 4

x - 4 - 1, - x - 4 - 1

f (x) = \frac{5 x}{x - 6}

- 4.9 t^{2} + 9.8 t

5 x + 7 y = 4 y - 2

3 x^{3}

f (x) = \frac{( \frac{x}{x + 5} )}{( \frac{x}{x + 5} ) + 5}

What is the inverse of f(x)=(x+1)^2+4 ?
The inverse of f(x)=(x+1)^2+4 is sqrt(x-4)-1,-sqrt(x-4)-1