What is the extreme 9e^{-3x}x-6e^{-3x} ?

The extreme 9e^{-3x}x-6e^{-3x} is Maximum(1, 3/(e^3))

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extreme 9e^{-3x}x-6e^{-3x}

extreme points

9 e^{- 3 x} x - 6 e^{- 3 x}

Maximum (1, \frac{3}{e ^{3}})

Solution steps

f^{'} (x) = - 27 e^{- 3 x} (x - 1)

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

9 e^{- 3 x} x - 6 e^{- 3 x} : \frac{3}{e ^{3}}

Maximum (1, \frac{3}{e ^{3}})

y = \frac{x ^{3} - 16 x}{- 4 x ^{2} + 4 x + 24}

f (x) = \frac{( x ^{2} - 5 x - 6 )}{x + 1}

f (x) = x^{3} + 5 x^{2} - 16 x - 80

3 x + 5 y = 5

What is the extreme 9e^{-3x}x-6e^{-3x} ?
The extreme 9e^{-3x}x-6e^{-3x} is Maximum(1, 3/(e^3))