What is the asymptotes of f(x)=((x^2-5x-6))/(x+1) ?

The asymptotes of f(x)=((x^2-5x-6))/(x+1) is Slant: y=x-6

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asymptotes of f(x)=((x^2-5x-6))/(x+1)

asymptotes

f (x) = \frac{( x ^{2} - 5 x - 6 )}{x + 1}

Slant : y = x - 6

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 5 x - 6}{x + 1} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 5 x - 6}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 5 x - 6}{x + 1} : y = x - 6

Slant : y = x - 6

f (x) = x^{3} + 5 x^{2} - 16 x - 80

3 x + 5 y = 5

x^{2} - 25

f (x) = - \frac{8}{9 x}

\frac{x ^{2} + x}{- 2 x ^{2} - 2 x + 12}

What is the asymptotes of f(x)=((x^2-5x-6))/(x+1) ?
The asymptotes of f(x)=((x^2-5x-6))/(x+1) is Slant: y=x-6