What is the domain of sqrt(x^2-25) ?

The domain of sqrt(x^2-25) is x = 5

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domain of sqrt(x^2-25)

domain

x^{2} - 25

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

The function domain

x \leq - 5 or x \geq 5

f (x) = - \frac{8}{9 x}

\frac{x ^{2} + x}{- 2 x ^{2} - 2 x + 12}

y = 2 x + 4

f (x) = - 8 x + 9

\frac{2 x ^{2} + 3}{x ^{2} + 1}

What is the domain of sqrt(x^2-25) ?
The domain of sqrt(x^2-25) is x<=-5\lor x>= 5