What is the critical f(x)=-1+4x-x^3 ?

The critical f(x)=-1+4x-x^3 is x=-2/(sqrt(3)),x= 2/(sqrt(3))

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critical f(x)=-1+4x-x^3

critical points

f (x) = - 1 + 4 x - x^{3}

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

- 1 + 4 x - x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

- 1 + 4 x - x^{3} : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{3}, x = \frac{2}{3}

f (x) = x + \frac{17}{x}

(8, 6), (- 4, - 3)

f (x) = \frac{- x ^{2} - 5 x + 2}{x + 3}

2 sin (\frac{1}{2})

x - 5

What is the critical f(x)=-1+4x-x^3 ?
The critical f(x)=-1+4x-x^3 is x=-2/(sqrt(3)),x= 2/(sqrt(3))