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Popular >

distance (8,6),(-4,-3)

Solution

distance

(8, 6), (- 4, - 3)

Solution

15

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(8, 6)

and

(- 4, - 3)

is

= (- 4 - 8)^{2} + (- 3 - 6)^{2}

Simplify

= 15

Popular Examples

asymptotes of f(x)=(-x^2-5x+2)/(x+3)asymptotes

f (x) = \frac{- x ^{2} - 5 x + 2}{x + 3}

range of 2sin(1/2)range

2 sin (\frac{1}{2})

domain of x-5 domain

x - 5

line-x+y=4 line

- x + y = 4

inverse of f(x)=((x-6)^{1/2})/7 inverse

f (x) = \frac{( x - 6 ) ^{\frac{1}{2}}}{7}

Frequently Asked Questions (FAQ)

What is the distance (8,6),(-4,-3) ?
The distance (8,6),(-4,-3) is 15