What is the inverse of f(x)=-1/4 (x^2-14x+13) ?

The inverse of f(x)=-1/4 (x^2-14x+13) is 7-2sqrt(-x+9),2sqrt(-x+9)+7

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inverse of f(x)=-1/4 (x^2-14x+13)

inverse

f (x) = - \frac{1}{4} (x^{2} - 14 x + 13)

7 - 2 - x + 9, 2 - x + 9 + 7

Solution steps

y = - \frac{1}{4} (x^{2} - 14 x + 13)

Replace

x

with

y

x = - \frac{1}{4} (y^{2} - 14 y + 13)

Solve for

y, x = - \frac{1}{4} (y^{2} - 14 y + 13)

7 - 2 - x + 9, 2 - x + 9 + 7

f (x) = x - 10

f (x) = \frac{x - 4}{x ^{2} + 20}

f (x) = \frac{2 x ^{2} - 20 x}{3 x - 30}

m = - \frac{1}{7}, (7, - 3)

f (x) = \frac{3}{5} x + 3

What is the inverse of f(x)=-1/4 (x^2-14x+13) ?
The inverse of f(x)=-1/4 (x^2-14x+13) is 7-2sqrt(-x+9),2sqrt(-x+9)+7