What is the range of 1/(sqrt(x-2)) ?

The range of 1/(sqrt(x-2)) is f(x)>0

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range of 1/(sqrt(x-2))

range

\frac{1}{x - 2}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{1}{x - 2} : x > 2

Extreme Points of

\frac{1}{x - 2} :

None

Find the range for the interval

2 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

y = 4 x - 3

f (x) = \frac{2}{r ^{2} + 1}

2 x^{3} + 8 x^{2} - 8 x - 32

f (x) = \frac{1}{x ^{2} - 6 x - 7}

f (x) = x^{2} - 2