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Popular >

midpoint (0,-9),(-3,5)

Solution

midpoint

(0, - 9), (- 3, 5)

Solution

(- \frac{3}{2}, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 9), (x_{2}, y_{2}) = (- 3, 5)

= (\frac{- 3 + 0}{2}, \frac{5 - 9}{2})

Refine

= (- \frac{3}{2}, - 2)

Popular Examples

inverse of y=16x^2+1 inverse

y = 16 x^{2} + 1

asymptotes of (3x)/(x+4)asymptotes

\frac{3 x}{x + 4}

y = x - 2

asymptotes of f(x)=(x^2-3x+1)/(x-2)asymptotes

f (x) = \frac{x ^{2} - 3 x + 1}{x - 2}

range of f(x)=x^2+5x+6 range

f (x) = x^{2} + 5 x + 6

Frequently Asked Questions (FAQ)

What is the midpoint (0,-9),(-3,5) ?
The midpoint (0,-9),(-3,5) is (-3/2 ,-2)