What is the critical f(x)=x^4-8x^2+10 ?

The critical f(x)=x^4-8x^2+10 is x=-2,x=0,x=2

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critical f(x)=x^4-8x^2+10

critical points

f (x) = x^{4} - 8 x^{2} + 10

x = - 2, x = 0, x = 2

Solution steps

x^{4} - 8 x^{2} + 10

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 8 x^{2} + 10 : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

f (x) = \frac{2 x ^{2} - 3 x + 5}{x ^{2} + 1}

f (x) = 5 x^{2} + 8 x - 2

(x - 5)^{2}

y = tan (\frac{5 x}{6})

f (x) = 0.09 x^{2} + 17 x + 350

What is the critical f(x)=x^4-8x^2+10 ?
The critical f(x)=x^4-8x^2+10 is x=-2,x=0,x=2