What is the inverse of f(x)=-9(x-3)^2-11 ?

The inverse of f(x)=-9(x-3)^2-11 is sqrt(-(x+11)/9)+3,-sqrt(-(x+11)/9)+3

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inverse of f(x)=-9(x-3)^2-11

inverse

f (x) = - 9 (x - 3)^{2} - 11

- \frac{x + 11}{9} + 3, - - \frac{x + 11}{9} + 3

Solution steps

y = - 9 (x - 3)^{2} - 11

Replace

x

with

y

x = - 9 (y - 3)^{2} - 11

Solve for

y, x = - 9 (y - 3)^{2} - 11

- \frac{x + 11}{9} + 3, - - \frac{x + 11}{9} + 3

f (x) = 3 x^{2} + 2 x

f (x) = \frac{1}{x ^{3} - x}

y + 6 = - \frac{1}{5} (x + 3), (- 5, - 9)

lo g_{4} (x - 4)

\frac{x ^{2} + x - 2}{x + 1}

What is the inverse of f(x)=-9(x-3)^2-11 ?
The inverse of f(x)=-9(x-3)^2-11 is sqrt(-(x+11)/9)+3,-sqrt(-(x+11)/9)+3