What is the asymptotes of f(x)=((4x^2-x))/((x^2-1)) ?

The asymptotes of f(x)=((4x^2-x))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((4x^2-x))/((x^2-1))

asymptotes

f (x) = \frac{( 4 x ^{2} - x )}{( x ^{2} - 1 )}

Vertical : x = - 1, x = 1, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} - x}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{4 x ^{2} - x}{x ^{2} - 1} : y = 4

Slant Asymptotes of

\frac{4 x ^{2} - x}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 4

f (x) = 4 x^{3} = 3 x^{4}

\frac{x ^{3} + x ^{2} - 6 x}{4 x ^{2} + 4 x - 8}

3.54

- x^{2} - 1

f (x) = \frac{9 x}{x ^{2} - 16}

What is the asymptotes of f(x)=((4x^2-x))/((x^2-1)) ?
The asymptotes of f(x)=((4x^2-x))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=4